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How do you simplify #sqrt147+6sqrt3#?

Answer 1

Isaiah Anthony

#sqrt(147)+6sqrt(3) = 13sqrt(3)#

#sqrt(147)+6sqrt(3) = sqrt(7^2*3)+6sqrt(3) = sqrt(7^2)sqrt(3)+6sqrt(3) = 7sqrt(3)+6sqrt(3) = 13sqrt(3)#

In general, when you are asked to simply anything like #sqrt(147)# start by factoring the radicand:

#147 = 3*7*7 = 3*7^2#

We can simplify the square root of this since it has a square factor, as previously demonstrated.

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Answer 2

Avery Alexander

To simplify sqrt147 + 6sqrt3, we can break down the square root of 147 into its prime factors. The prime factorization of 147 is 3 * 7 * 7. Simplifying the square root of 147 gives us 7sqrt3. Therefore, the simplified expression is 7sqrt3 + 6sqrt3, which equals 13sqrt3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.