How do you simplify #sqrt12 times sqrt27#?

Answer 1

18

You know that

#sqrt(12)=sqrt(2^2*3)=2sqrt(3)#

and

#sqrt(27)=sqrt(3^3)=3sqrt(3)#

so you can sum them:

#sqrt(12)*sqrt(27)=2sqrt(3)*3sqrt(3)=6sqrt(3)^2=6*3=18#
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Answer 2

To simplify sqrt12 times sqrt27, we can multiply the numbers inside the square roots. sqrt12 is equal to 2sqrt3, and sqrt27 is equal to 3sqrt3. Multiplying these two expressions gives us 6sqrt9, which simplifies to 6 times 3, resulting in 18. Therefore, sqrt12 times sqrt27 simplifies to 18.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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