How do you simplify #sqrt(75)#?

Answer 1

#5sqrt3#

We can simplify radicals using square numbers.

Start by listing the factors:

#75 and 1# #25 and 3# #15 and 5#
#25# is a squared number, so we can use #25# and #3#
#rArr sqrt25 xx sqrt3#
#sqrt25# can be simplified:
#sqrt25=5#
#therefore# #rArr 5sqrt3#
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Answer 2

#sqrt(75)=5sqrt(3)#

#sqrt(75)=sqrt(5^2 * 3) =sqrt(5^2) * sqrt(7)=5 * sqrt(7)#
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Answer 3

To simplify sqrt(75), we first factorize 75 into its prime factors, which are 3 and 5, since 3 * 5 * 5 = 75. Then, we take out pairs of identical prime factors from under the square root. So, sqrt(75) = sqrt(3 * 5 * 5) = sqrt(3 * 25). Since sqrt(25) = 5, sqrt(3 * 25) = 5sqrt(3). Therefore, sqrt(75) simplifies to 5sqrt(3).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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