How do you simplify #sqrt(32xy^2) div sqrt4#?

Answer 1

#ysqrt(8x)#

#sqrt(32xy^2)-:sqrt4# #=(sqrt32xxsqrtx xxsqrt(y^2))-:sqrt4# #=(cancel(sqrt4)xxsqrt8xxsqrtx xxy)-:cancel(sqrt4# #=yxxsqrt8xxsqrtx# #=ysqrt(8x)#

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Answer 2

Eva Abramson

To simplify sqrt(32xy^2) div sqrt4, we can simplify each term separately.

First, let's simplify sqrt(32xy^2). We can break down 32 into its prime factors: 32 = 2^5. Similarly, we can break down y^2 into y * y.

So, sqrt(32xy^2) becomes sqrt(2^5 * x * y * y), which simplifies to 2^2 * y * sqrt(2x).

Next, let's simplify sqrt4. The square root of 4 is 2.

Now, we can divide sqrt(32xy^2) by sqrt4. Dividing by 2 is the same as multiplying by 1/2.

Therefore, sqrt(32xy^2) div sqrt4 simplifies to (2^2 * y * sqrt(2x)) * (1/2), which further simplifies to 2y * sqrt(2x).

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Answer 3

Abigail Allen

( \sqrt{32xy^2} \div \sqrt{4} = \sqrt{\frac{32xy^2}{4}} = \sqrt{8xy^2} )

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.