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How do you simplify #sqrt(15x) times sqrt(21x)#?

Answer 1

Eva Abramson

#3xsqrt(35)#

Notice that 3 is a factor of both 15 and 21 and so is #x#

#sqrt(3xx5xx x)xxsqrt(3xx7xx x)#

#sqrt(3x)xxsqrt(5)xx sqrt(3x)xxsqrt(7)#

But #sqrt(3x)xxsqrt(3x)=3x#

#3xsqrt(5)sqrt(7) = 3xsqrt(5xx7)=3xsqrt(35)#

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Answer 2

Julia Adams

#sqrt(15x)*sqrt(21x)=3xsqrt(35)#

#sqrt(15x)*sqrt(21x)#

#sqrt((15x)*(21x))#

#sqrt((3)(5)x*3(7)x)#

#sqrt(3^2*x^2*35)#

#3xsqrt(35)#

God bless....I hope the explanation is useful.

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Answer 3

Genesis Allen

To simplify sqrt(15x) times sqrt(21x), you can multiply the numbers under the square roots together and combine the variables.

sqrt(15x) times sqrt(21x) simplifies to sqrt(15x * 21x) which is equal to sqrt(315x^2).

Further simplifying, sqrt(315x^2) can be written as sqrt(315) times sqrt(x^2).

The square root of 315 can be simplified to 3sqrt(35).

Therefore, sqrt(15x) times sqrt(21x) simplifies to 3sqrt(35)x.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.