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How do you simplify #(root3y)+5(root3y)#?

Answer 1

Avery Alexander

#(root(3)y) + 5(root(3)y)=6(root(3)y)#

Simplify:

#(root(3)y) + 5(root(3)y)=#

#6(root(3)y)#

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Answer 2

Hazel Anglin

#6root3(y)#

The first thing is to notice that there are two terms. (There is a + sign between them.)

Then notice that the terms themselves are the same. That means they can be added.

If we had #2x + 7x# we would add and get #9x# If no number is shown it means #1#.

#x+5x =6x#

In our case the terms are in #root3(y)#

To simplify, add the coefficients.

#1(root3(y))+5(root3(y))#

#=6(root3(y))#

The brackets are not necessary.

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Answer 3

Avery Alexander

To simplify (root3y) + 5(root3y), you can combine the like terms. The like terms in this expression are both the terms with the square root of 3y. Adding them together gives you 6(root3y).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.