How do you simplify #root3(351 )#?

Answer 1

First factorize 351. we get 351 = 333*13.

Now #root(3) 351 = (351)^(1/3) = (3.3.3.13)^(1/3)#
= #[3^1 . 3^1 . 3^1 .13]^(1/3) #
=#[3^(1+1+1) . 13]^(1/3)#
=#[3^3 . 13]^(1/3)#
= #[3^(3*1/3) . 13]^(1/3)#
=#3root(3) 13#
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Answer 2

To simplify ( \sqrt{3} \times 351 ), first, factor 351 to find perfect squares:

[ 351 = 3 \times 117 ]

Next, we can rewrite ( 351 ) as ( 3 \times 117 ), and since ( 3 ) is a perfect square, we can take it out of the square root:

[ \sqrt{3} \times 351 = \sqrt{3} \times 3 \times 117 ]

[ = 3 \sqrt{3} \times 117 ]

So, ( \sqrt{3} \times 351 ) simplifies to ( 3 \sqrt{3} \times 117 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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