How do you simplify #root3(2)*root3(5)#?

Answer 1

Because they have the same radical-grade, you may just multiply the arguments.

#=root 3 (2*5)=root 3 10#
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Answer 2

To simplify √3(2) * √3(5), we can multiply the numbers inside the square roots together.

√3(2) * √3(5) = √(3 * 2) * √(3 * 5)

Simplifying further, we have:

√6 * √15

Since both square roots have the same index (3), we can combine them into a single square root:

√6 * √15 = √(6 * 15)

Multiplying the numbers inside the square root gives us:

√(90)

Therefore, the simplified form of √3(2) * √3(5) is √90.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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