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How do you simplify #root(3)432#?

Answer 1

Roman Alvarez

#root(3)432=6root(3)2#

To simplify #root(3)432# let us first factorize #432#

#432=2xx2xx2xx2xx3xx3xx3#

Hence #root(3)432#

= #root(3)(2xxul(2xx2xx2xx3xx3xx3))#

= #2xx3xxroot(3)2#

= #6root(3)2#

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Answer 2

Mila Anderson

To simplify ( \sqrt[3]{432} ), you can factorize 432 into prime factors and then take the cube root of each factor:

[ 432 = 2^4 \times 3^3 ]

Now, take the cube root of each factor:

[ \sqrt[3]{432} = \sqrt[3]{2^4 \times 3^3} ]

[ = \sqrt[3]{2^3 \times 2 \times 3^3} ]

[ = 2 \times \sqrt[3]{2 \times 3^3} ]

[ = 2 \times \sqrt[3]{54} ]

So, ( \sqrt[3]{432} ) simplifies to ( 2\sqrt[3]{54} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.