How do you simplify #(r+6)/(6+r)#?

Question

Avery Alexander · Accepted Answer

See explanation.

We can write that since the order of the operands has no bearing on the addition result: Being aware that we are able to write: The above equality is true for all #x# for which the value is defined, i.e. for all real values other than #r=-6#.

Savannah Anderson · Answer

#1#

We have the same thing on the numerator and the same thing on the denominator, thus this expression is equal to #1#.

#r+6# is the same as #6+r#, because addition is commutative. Thus, we would have:

#(r+6)/(r+6)#

The terms would cancel with each other, and we would essentially be left with a #1#. We can view this as the coefficient on the #r# term.

In general, #a/a=1#. So if the top and bottom of a fraction is the same, it is equal to #1#.

I hope this is useful.

Savannah Anderson · Answer

#(r+6)/(6+r)=1# addition is commutative, so : #r+6=6+r#, and trivially you have #(r+6)/(6+r)=1#

Julia Adams · Answer

#1# Think about it: #r+ 6 = 6 + r# Therefore, the numerator and the denominator can cancel each other out to have a total value of #1#.

Eva Abramson · Answer

undefined To simplify (r+6)/(6+r), you can rewrite it as 1.