How do you simplify #(m^7n^4p)/(m^3n^3p)#?

Answer 1

#m^4n# (if #m, n,p,# are all non-zero)

We know that #a^m/a^n = a^(m-n)#, for #a!=0#.
So, provided #m, n,p,# are all non-zero, the result is:
#m^7/m^3 n^4/n^3 p/p = m^4n#
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Answer 2

To simplify (\frac{m^7n^4p}{m^3n^3p}), you subtract the exponents of like bases in the numerator and denominator. This yields (m^{7-3}n^{4-3}p^{1-1}), which simplifies to (m^4np^0). Since (p^0) equals 1, the expression further simplifies to (m^4n).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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