How do you simplify #\frac { 4} { 3} + \frac { 5} { 2x + 6}#?
we need to put it over a common denominator; the simplest way to achieve this is to follow the 'cross multiplication method'
now we simplify
usually we leave the denominator factorised
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To simplify the expression ( \frac{4}{3} + \frac{5}{2x + 6} ), you first need to find a common denominator for both fractions. In this case, the least common denominator is (3(2x + 6)), which is the least common multiple of 3 and (2x + 6).
Now, rewrite each fraction with the common denominator:
[ \frac{4}{3} + \frac{5}{2x + 6} = \frac{4(2x + 6)}{3(2x + 6)} + \frac{5(3)}{3(2x + 6)} ]
Next, simplify each fraction:
[ = \frac{8x + 24}{3(2x + 6)} + \frac{15}{3(2x + 6)} ]
Now that both fractions have the same denominator, you can combine them:
[ = \frac{(8x + 24) + 15}{3(2x + 6)} ]
[ = \frac{8x + 24 + 15}{3(2x + 6)} ]
[ = \frac{8x + 39}{3(2x + 6)} ]
So, ( \frac{4}{3} + \frac{5}{2x + 6} ) simplifies to ( \frac{8x + 39}{3(2x + 6)} ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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