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How do you simplify #\frac { 3x ^ { 3} y ^ { 2} } { 2x ^ { 2} y ^ { 3} }#?

Answer 1

Julia Adams

#(3x)/(2y)# or I prefer it as #1.5xy^-1=(1.5x)/y#.

Given: #(3x^3y^2)/(2x^2y^3)#.

Separate into:

#=3/2*x^3/x^2*y^2/y^3#

#=1.5*x*1/y#

#=(1.5x)/y#

#=1.5xy^-1#

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Answer 2

Kennedy Adams

Here.

Start by crossing out the #x# of the numerator with that of the denominator using indices rules.

#x^3/x^2 = x#

That's because the rule of indices states that when powers are divided, they get subtracted.

Do the same for the #y#.

You get:

#y^2/ y^3= 1/y#

Now since you can't simplify the 2 and the 3, you can leave them:

#(3x)/(2y)#

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Answer 3

Savannah Anderson

To simplify the expression \frac { 3x ^ { 3} y ^ { 2} } { 2x ^ { 2} y ^ { 3} }, you can divide the coefficients and subtract the exponents of the variables. This simplifies to \frac { 3 } { 2x y }.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.