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How do you simplify #(cos2x+sin^2x)/cos^2x#?

Answer 1

Nolan Alexander

#1#

Recall the identity #cos2x=cos^2x-sin^2x#. Applying it, we get

#(cos^2xcancel(-sin^2x+sin^2x))/cos^2x=cancel(cos^2x)/cancel(cos^2x)=1#

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Answer 2

Dylan Arnold

To simplify (cos^2x + sin^2x) / cos^2x, we can use the trigonometric identity cos^2x + sin^2x = 1.

Substituting this identity into the expression, we get:

(1) / cos^2x

Since 1 / cos^2x is equal to sec^2x (by the definition of secant function), the simplified form of the expression is sec^2x.

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Answer from HIX Tutor

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