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How do you simplify completely #(12x^3-4x^2+8x)/(-2x)#?

Answer 1

Genesis Allen

Provided #x!= 0#

#(12x^3-4x^2+8x)/(-2x)#

#= (12x^3)/(-2x) +(-4x^2)/(-2x) + (8x)/(-2x)#

#= -6x^2+2x-4#

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Answer 2

Kennedy Adams

To simplify ( \frac{12x^3 - 4x^2 + 8x}{-2x} ), we divide each term in the numerator by the denominator:

[ \frac{12x^3}{-2x} - \frac{4x^2}{-2x} + \frac{8x}{-2x} ]

This simplifies to:

[ -6x^2 + 2x - 4 ]

So, ( \frac{12x^3 - 4x^2 + 8x}{-2x} ) simplifies to ( -6x^2 + 2x - 4 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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