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How do you simplify # (bc)/(pia) + (ac)/(pib) + (ab)/(pi*c)#?

Answer 1

#(b^2c^2+a^2c^2+a^2b^2)/(pi*abc)#

#(bc)/(pi*a) + (ac)/(pi*b) + (ab)/(pi*c)# #=(b^2c^2)/(pi*abc) + (a^2c^2)/(pi*abc) + (a^2b^2)/(pi*abc)# #=(b^2c^2+a^2c^2+a^2b^2)/(pi*abc)#

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Answer 2

Genesis Allen

To simplify the expression (bc)/(pia) + (ac)/(pib) + (ab)/(pi*c), we can find a common denominator and combine the fractions. The common denominator is pi * a * b * c.

Multiplying the first fraction by (b * c) / (b * c), the second fraction by (a * c) / (a * c), and the third fraction by (a * b) / (a * b), we get:

[(bc * b * c) + (ac * a * c) + (ab * a * b)] / (pi * a * b * c)

Simplifying the numerator, we have:

(b^2 * c^2 + a^2 * c^2 + a^2 * b^2) / (pi * a * b * c)

Therefore, the simplified expression is:

(b^2 * c^2 + a^2 * c^2 + a^2 * b^2) / (pi * a * b * c)

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you simplify # (bc)/(pi*a) + (ac)/(pi*b) + (ab)/(pi*c)#?

How do you simplify # (bc)/(pia) + (ac)/(pib) + (ab)/(pi*c)#?