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How do you simplify #(b^2)^-6/b^-4#?

Answer 1

Savannah Anderson

#=((b^2)^-6)/b^-4=b^-12xxb^4=b^(-12+4)=b^-8#

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Answer 2

Abigail Allen

To simplify ( \frac{(b^2)^{-6}}{b^{-4}} ), you can apply the power of a power property, which states that ( (a^m)^n = a^{mn} ). So, ( (b^2)^{-6} = b^{2 \times -6} = b^{-12} ). Then, you can use the quotient rule of exponents, which states that ( \frac{a^m}{a^n} = a^{m-n} ). Thus, ( \frac{(b^2)^{-6}}{b^{-4}} = b^{-12 - (-4)} = b^{-12 + 4} = b^{-8} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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