How do you simplify and restricted value of #(x^2+12x +36)/(9x+18)#?

Answer 1

Excluded value #->x=-2#

I am not convinced that this can be simplified any further than it already is.

If you factor out you get :#" " ((x+6)(x+6))/(9(x+2))# and I can not spot anything that can be don with this.
The excludes value is #x=-2# as this turns the denominator into 0 which is undefined.
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Answer 2

To simplify the expression (x^2+12x+36)/(9x+18), we can first factor the numerator and the denominator. The numerator can be factored as (x+6)(x+6), and the denominator can be factored as 9(x+2).

Therefore, the expression simplifies to (x+6)(x+6)/(9(x+2)).

To find the restricted values, we need to identify the values of x that would make the denominator equal to zero. In this case, the restricted value is x = -2, since it would make the denominator 9(-2+2) = 0.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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