How do you simplify and restricted value of #5/(7z+5)#?

Answer 1

#z!=-5/7#

#"since neither the numerator nor denominator can be"# #"factored then fraction is described in simplest form"#
#rArr5/(7z+5)larrcolor(blue)" is in simplest form"#

The denominator cannot be zero as this would make the fraction undefined. Equating the denominator to zero and solving gives the value that z cannot be.

#"solve "7z+5=0rArrz=-5/7larrcolor(red)" restricted value"#
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Answer 2

To simplify the expression 5/(7z+5), you can't simplify it any further. However, to find the restricted value, you need to set the denominator equal to zero and solve for z. In this case, 7z+5 = 0. Solving this equation, you get z = -5/7. Therefore, the restricted value of 5/(7z+5) is z = -5/7.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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