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How do you simplify and find the restrictions for #(6)/(x+3)#?

Answer 1

See explanation

The function #6/(x+3)# will have a restricted domain at #x=-3#.

We know this because the denominator of our function cannot be #0# and to find what value this occurs, we set the denominator equal to #0# such that:

#x+3=0 -> x=-3#

What this tells us that the graph will have a vertical asymptote at #x=-3#

Thus our domain for this function is: #{x| x!= -3} or (-oo,-3) uu (-3,oo)#

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Answer 2

Genesis Allen

To simplify the expression (6)/(x+3), you can divide the numerator (6) by the denominator (x+3). This simplifies to 6/(x+3).

To find the restrictions, you need to identify any values of x that would make the denominator equal to zero, as division by zero is undefined. In this case, the denominator (x+3) would be equal to zero if x = -3. Therefore, the restriction for this expression is that x cannot be equal to -3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.