How do you simplify and find the excluded value of #(3x^2 - 3) /( 6x - 6 )#?

Question

Eli Assouline · Accepted Answer

excluded value is x = 1 for unsimplified expression
no excluded value for simplified expression
simplified: #(x + 1)/2# factor numerator: #3(x^2 - 1)# = #3(x - 1)(x + 1)# factor denominator: #6(x - 1)# #(3(x-1)(x+1))/(6(x-1))# which simplifies to #(x +1)/2# to find excluded value set denominator = 0 and solve for variable to find excluded value. Since cannot divide by 0, any value of the variable that makes the denominator = 0 is excluded #6(x - 1) = 0# #-> (x - 1) = 0 -> x = 1#

Jace Anderson · Answer

undefined To simplify the expression (3x^2 - 3) / (6x - 6), we can factor out a common factor of 3 from both the numerator and denominator, resulting in (3(x^2 - 1)) / (6(x - 1)).

Next, we can simplify further by canceling out the common factor of 3, giving us (x^2 - 1) / (2(x - 1)).

To find the excluded value, we need to identify any values of x that would make the denominator equal to zero. In this case, if we set the denominator 2(x - 1) equal to zero and solve for x, we find that x = 1.

Therefore, the excluded value for this expression is x = 1.