# How do you simplify and find the excluded value of #(3) / (x+1) + (5) / ( x - 1) #?

First we say that

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To simplify and find the excluded value of (3) / (x+1) + (5) / (x-1), we need to find a common denominator and combine the fractions. The common denominator is (x+1)(x-1).

Multiplying the first fraction by (x-1)/(x-1) and the second fraction by (x+1)/(x+1), we get:

(3(x-1))/((x+1)(x-1)) + (5(x+1))/((x+1)(x-1))

Expanding and combining the numerators, we have:

(3x - 3 + 5x + 5)/((x+1)(x-1))

Combining like terms in the numerator, we get:

(8x + 2)/((x+1)(x-1))

The excluded value is the value of x that makes the denominator equal to zero. In this case, the excluded values are x = -1 and x = 1.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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