# How do you simplify and find the excluded value of #(2x^2+6x+4)/(4x^2-12x-16)#?

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The first step in algebraic fractions is to factor as far as possible:

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To simplify the expression (2x^2+6x+4)/(4x^2-12x-16), we can first factor both the numerator and denominator. The numerator can be factored as 2(x+2)(x+1), and the denominator can be factored as 4(x-2)(x+2).

Next, we can cancel out any common factors between the numerator and denominator. In this case, we can cancel out the (x+2) term.

After canceling out the common factor, the simplified expression becomes 2(x+1)/(4(x-2)).

To find the excluded value, we need to determine the value(s) of x that would make the denominator equal to zero. In this case, the excluded value is x = 2, as it would make the denominator 4(2-2) = 0.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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