How do you simplify #abs(((31)+5)div(2))#?
Bracket within brackets is called nested brackets. In this situation you consider each pair of brackets working outwards
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A number's absolute value is always positive, but before we can calculate its absolute value, we must first simplify its contents. Let's do that now:
First, it's a little hard to see what's going on, so to help a little, I'll add some color. Specifically, I'll color a term that is inside brackets and needs to be completed before we can complete the division (which is the operation that initially caught my attention):
Thus, I will complete the green portion independently and then return the result:
Let's now return the solution to this section to the original:
then we are able to obtain the absolute value:
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To simplify the expression abs(((31)+5) ÷ (2)), follow the order of operations (PEMDAS/BODMAS):

Simplify the expression inside the parentheses: (3  1) = 2

Add 5 to the result: 2 + 5 = 3

Divide the result by 2: 3 ÷ (2) = 1.5

Find the absolute value of the result: abs(1.5) = 1.5
Therefore, the simplified expression is 1.5.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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