How do you simplify #abs((-(3-1)+5)div(-2))#?
Bracket within brackets is called nested brackets. In this situation you consider each pair of brackets working outwards
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A number's absolute value is always positive, but before we can calculate its absolute value, we must first simplify its contents. Let's do that now:
First, it's a little hard to see what's going on, so to help a little, I'll add some color. Specifically, I'll color a term that is inside brackets and needs to be completed before we can complete the division (which is the operation that initially caught my attention):
Thus, I will complete the green portion independently and then return the result:
Let's now return the solution to this section to the original:
then we are able to obtain the absolute value:
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To simplify the expression abs((-(3-1)+5) ÷ (-2)), follow the order of operations (PEMDAS/BODMAS):
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Simplify the expression inside the parentheses: -(3 - 1) = -2
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Add 5 to the result: -2 + 5 = 3
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Divide the result by -2: 3 ÷ (-2) = -1.5
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Find the absolute value of the result: abs(-1.5) = 1.5
Therefore, the simplified expression is 1.5.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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