How do you simplify #abs(11-pi)#?

Answer 1

#abs(11-pi) = color(blue)(11-pi)# or, approximately, #color(blue)(7.85841)#

Simply put, #pi# is a number that is smaller than #11#.
Thus, 11-pi > 0# for #color(white)("XXX") and 11-pi# for #color(white)("XXX")abs(11-pi)
Assuming #pi=3.14159# and #color(white)("XXX")11-pi=7.85841#, we can calculate
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Answer 2

To simplify ( \text{abs}(11 - \pi) ), you just need to compute the absolute value of the expression, which means taking the positive distance between ( 11 ) and ( \pi ). So, the simplified form is ( 11 - \pi ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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