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How do you simplify #(9x + 10xy) / x#?

Answer 1

Abigail Allen

#9+10y#

#"factor numerator and cancel common factor"#

#=(cancel(x)(9+10y))/cancel(x)=9+10y#

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Answer 2

Genesis Allen

#=9+10y#

#(9x+10xy)/x" "larr# factorise the numerator

#=(cancelx(9+10y))/cancelx" "larr# cancel

#= 9+10y#

You can also write two fractions and simplify each.

#(9x)/x + (10xy)/x#

#=9+10y#

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Answer 3

Julia Adams

#9+10y#

#9x+10xy# can be factorised to become #x(9+10y)#

so #(9x+10xy)/x=(x(9+10y))/x=(cancelx(9+10y))/cancelx=9+10y#

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Answer 4

Hazel Anglin

To simplify (9x + 10xy) / x, you can divide each term in the numerator by x. This gives you 9 + 10y.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.