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How do you simplify #9+ (x-3)/ (x+2)#?

Answer 1

Isaiah Anthony

The simplified expression is #(10x+15)/(x+2)#.

Multiply #9# by #(x+2)/(x+2)# to get a common denominator, then combine the two fractions:

#color(white)=9+(x-3)/(x+2)#

#=9color(red)(*((x+2))/(x+2))+(x-3)/(x+2)#

#=(9(x+2))/(x+2)+(x-3)/(x+2)#

#=(9x+9*2)/(x+2)+(x-3)/(x+2)#

#=(9x+18)/(x+2)+(x-3)/(x+2)#

#=((9x+18)+(x-3))/(x+2)#

#=(9x+18+x-3)/(x+2)#

#=(9x+x+18-3)/(x+2)#

#=(10x+18-3)/(x+2)#

#=(10x+15)/(x+2)#

That's it. Hope this helped!

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Answer 2

Eva Abramson

To simplify 9+ (x-3)/ (x+2), you can start by simplifying the expression within the parentheses. This gives you 9 + x - 3 / (x + 2). Next, you can combine like terms by adding 9 and x, which gives you x + 9 - 3 / (x + 2). Finally, you can simplify further by subtracting 3 from 9, resulting in x + 6 / (x + 2).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.