How do you simplify #(9.04times10^6)(5.2times10^-4)#?

Answer 1

To simplify (9.04 × 10^6)(5.2 × 10^-4), multiply the coefficients (9.04 × 5.2) and add the exponents of 10 (6 + (-4)).

9.04 × 5.2 = 47.008 10^(6 + (-4)) = 10^2 = 100

So, the simplified expression is 47.008 × 10^2.

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Answer 2

#4.7008xx10^3#

#9.04xx5.2=47.008#
#10^6xx10^(-4)=10^(6+ -4)=10^2#
#(9.04xx10^6)(5.2xx10^(-4))=47.008xx10^2#
#4.7008xx10^3#
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Answer 3

See a solution process below:

First, rewrite the expression as:

#9.04 xx 10^6 xx 5.2 xx 10^-4 =>#
#9.04 xx 5.2 xx 10^6 xx 10^-4 =>#
#(9.04 xx 5.2) xx (10^6 xx 10^-4) =>#
#47.008 xx (10^6 xx 10^-4)#

Next, multiply the two 10s terms using this rule for exponents:

#x^color(red)(a) xx x^color(blue)(b) = x^(color(red)(a) + color(blue)(b))#
#47.008 xx (10^color(red)(6) xx 10^color(blue)(-4) =>#
#47.008 xx 10^(color(red)(6) + color(blue)(-4)) =>#
#47.008 xx 10^(color(red)(6) - color(blue)(4)) =>#
#47.008 xx 10^2#

To put this expression into scientific notation we must move the decimal point one place to the left so we need to add 1 to the 10s exponent:

#47.008 xx 10^2 =>#
#4.7008 xx 10^3#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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