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How do you simplify #7x^3(2x^2)^2/(10x^5)#?

Answer 1

Genesis Allen

It is #7x^3(2x^2)^2/(10x^5)=7x^3*(4x^4)/(10x^5)=(28*x^7)/(10x^5)=14/5*x^2#

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Answer 2

Julia Adams

The answer is #(14x^2)/5#.

Simplify #7x^3(2x^2)^2/(10^5)# to #((7x^3)(2x^2)^2)/(10x^5)# .

#((7x^3)(2x^2)^2)/(10x^5)#

Apply the exponent rule #(a^m)^n=a^(m*n)#

#((7x^3)(4x^4))/(10x^5)#

Apply the exponent rule #a^mxxa^n=a^(m+n)#.

#(28x^(3+4))/(10x^5)=#

#(28x^7)/(10x^5)#

Apply the exponent rule #a^m/a^n=a^(m-n)#.

#(28x^(7-5))/10=#

#(28x^2)/10#

Reduce #28/10# to #14/5=#.

#(14x^2)/5#

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Answer 3

Jameson Allen

To simplify ( \frac{7x^3(2x^2)^2}{10x^5} ), you would first simplify the expression inside the parentheses:

( (2x^2)^2 = 4x^4 )

Then, you would multiply 7x^3 by 4x^4:

( 7x^3 \times 4x^4 = 28x^7 )

Finally, you would divide by 10x^5:

( \frac{28x^7}{10x^5} = \frac{28}{10}x^{7-5} = \frac{14}{5}x^2 )

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.