How do you simplify #7i*3i(-8-6i)#?
The first step is to multiply 7i and 3i together.
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To simplify (7i \times 3i \times (-8 - 6i)), we first multiply the complex numbers:
[ 7i \times 3i = 21i^2 ]
Recall that (i^2 = -1), so:
[ 21i^2 = 21(-1) = -21 ]
Now, we have:
[ -21 \times (-8 - 6i) = 168 + 126i ]
Therefore, (7i \times 3i \times (-8 - 6i)) simplifies to (168 + 126i).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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