How do you simplify #(7+w)/(-7-w)#?

Answer 1

See a solution process below:

Rewrite the denominator as follows first:

#(7 + w)/(-1(7 + w)#

Next, remove all common terms from the denominator and numerator:

#color(red)(cancel(color(black)(7 + w)))/(-1color(red)(cancel(color(black)((7 + w))))) => 1/-1 = -1#
How, because we cannot divide by #0# in the original expression we need to restrict as:
Where #x != -7#
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Answer 2

To simplify the expression (7+w)/(-7-w), you can start by multiplying both the numerator and denominator by -1 to eliminate the negative signs. This gives you -(7+w)/(7+w). Since the numerator and denominator are the same, you can cancel them out, resulting in -1 as the simplified form.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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