How do you simplify #7/8 - (4/5 + 1 3/4)#?

Answer 1

#-67/40#

There is a mixed number in the expression. Let's make that an improper fraction: #\color(red)(1(3/4)=4/4+3/4=7/4)# #\therefore7/8-(4/5+\color(red)(7/4))# Now make everything common denominator. That means LCM of 8, 5, 4 (which is 40).

Thus: #7/8(5/5)-[4/5(8/8)+7/4(10/10)]#

#(7(5)-[4(8)+7(10)])/40=(35-(32+70))/40#

Now we can apply PEMDAS.

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Answer 2

Julia Adams

To simplify ( \frac{7}{8} - \left( \frac{4}{5} + \frac{1}{4} \right) ), first, simplify the expression inside the parentheses: ( \frac{4}{5} + \frac{1}{4} = \frac{16}{20} + \frac{5}{20} = \frac{21}{20} ). Then, subtract this result from ( \frac{7}{8} ): ( \frac{7}{8} - \frac{21}{20} = \frac{35}{40} - \frac{42}{40} = -\frac{7}{40} ). So, ( \frac{7}{8} - \left( \frac{4}{5} + \frac{1}{4} \right) = -\frac{7}{40} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.