How do you simplify #(6y^3 - 12y^2) /(12y^2 - 18)#?

Question

HIX Tutor · Accepted Answer

undefined To simplify (6y^3 - 12y^2) / (12y^2 - 18), follow these steps:

Step 1: Factor out common terms from the numerator and the denominator.
Step 2: Simplify the expression by canceling out common factors if possible.
Step 3: Write the simplified expression.

Let me know if you need help with any of the steps!

Eva Adamson · Answer

Factor out the GCF in the numerator and denominator. Cancel the #6# in the numerator and denominator.

#(6y^3-12y^2)/(12y^2-18)# Numerator #6y3-12y^2# Factor out #6y^2# #6y^2(y-2)# Denominator #(12y^2-18)# Factor out #6#. #6(2y^2-3)# Put them back together. #((cancel6y^2)(y-2))/((cancel6)(2y^2-3))# = #((y^2)(y-2))/(2y^2-3)#

Nathan Axel · Answer

undefined To simplify the expression (6y^3 - 12y^2) /(12y^2 - 18), we can factor out a common factor from both the numerator and the denominator. In this case, the common factor is 6y^2. Factoring out 6y^2 from the numerator and denominator gives us:

(6y^2(y - 2))/(6y^2(2y^2 - 3))

Next, we can cancel out the common factor of 6y^2 from both the numerator and the denominator:

(y - 2)/(2y^2 - 3)

Therefore, the simplified form of (6y^3 - 12y^2) /(12y^2 - 18) is (y - 2)/(2y^2 - 3).