How do you simplify # (6y – 2) + (7y + 3) – (2y – 6)#?

Answer 1

#11y+7#

First We have to expand : #(6y-2) + (7y+3) -(2y-6)#
=#6y -2 + 7y +3 -2y +6#

Now adding the same unknowns we have:

#6y - 2 + 7y +3 - 2y + 6#
=#6y +7y -2y -2 +3 +6#
=#11y +7#
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Answer 2

To simplify the expression ( (6y - 2) + (7y + 3) - (2y - 6) ), follow these steps:

  1. Remove parentheses, keeping in mind to distribute the minus sign to the terms of the last expression: ( 6y - 2 + 7y + 3 - 2y + 6 ).
  2. Combine like terms: ( (6y + 7y - 2y) + (-2 + 3 + 6) ).
  3. Simplify the terms: ( 11y + 7 ).

So, the simplified expression is ( 11y + 7 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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