How do you simplify #(64-c^2)/(c^2-7c-8)# and what are the ecluded values fot he variables?

Answer 1

this expression can be simplified to #-(c + 8)/(c + 1)# with restrictions of #c!= 8# and #c!=-1#.

Factor.

#=-(c^2 - 64)/(c^2 - 7c - 8)#
#=-((c + 8)(c - 8))/((c - 8)(c + 1))#
#=-(c + 8)/(c + 1)#
As for the excluded values, these are found by setting the denominator of the initial expression to #0# and solving for the variable.
#c^2 - 7c - 8 = 0#
#(c - 8)(c + 1)#
#c = 8 and -1#
Hence, #c!= 8# and #c!=-1#.

Hopefully this helps!

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Answer 2

To simplify (64-c^2)/(c^2-7c-8), we can factor the numerator and denominator. The numerator can be factored as the difference of squares: (8-c)(8+c). The denominator can be factored as (c-8)(c+1).

Therefore, the simplified expression is (8-c)(8+c)/(c-8)(c+1).

The excluded values for the variables are the values that would make the denominator equal to zero. In this case, the excluded values are c = 8 and c = -1, as they would result in division by zero.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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