How do you simplify #6 sqrt5 - 2sqrt5#?

Answer 1

It's pretty simple, actually: #6sqrt5- 2sqrt5=4sqrt5#

What we can do, is we can create a variable for the #sqrt5# and then substitute back after we do the math.

Let's say #x# can be equal to #sqrt5#. So then our simplified question would read: #6x-2x# when we place #x# in for the #sqrt5#.

#6x-2x=4x# so then we just take the #sqrt5# and place it back in for the #x# and we get #4sqrt5#.

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Answer 2

Avery Alexander

4#sqrt#5

#sqrt#5(6-2) = 4#sqrt#5

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Answer 3

Eli Assouline

To simplify 6√5 - 2√5, you can combine the like terms. Both terms have the same radical (√5), so you can subtract the coefficients (numbers in front of the radical).

6√5 - 2√5 simplifies to 4√5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.