How do you simplify #[(6+7) + 3²] times (4÷ 8) # using PEMDAS?

Answer 1

#11#

Order of operations: multiply and divide first, then add and subtract, always starting with brackets.

#therefore[(6+7)+3^2]xx(4-:8) = (13+9) xx 1/2#
#=22 xx 1/2#
#=11#
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Answer 2

To simplify the expression [(6+7) + 3²] × (4÷ 8) using PEMDAS:

  1. First, perform the operations inside the parentheses: (6+7) = 13 and 3² = 9.
  2. Then, perform the exponentiation: 3² = 9.
  3. Next, perform the addition inside the first set of parentheses: (13 + 9) = 22.
  4. Then, perform the division: 4 ÷ 8 = 0.5.
  5. Finally, multiply the results: 22 × 0.5 = 11.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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