How do you simplify #6^3 - 3 times (3^2 times 2) + 5# using order of operations?

Answer 1

We can use the BODMAS rule to solve this.

#167#

The order of operations is given by the BODMAS rule. B=Brackets; O=Of; D=Division; M=Multiplication; A=Addition; S=Subtraction. B i.e. brackets have highest priority and the priority decreases till S i.e. subtraction.

#6^3-3*(3^2*2)+5#

= #6*6*6-3*(9*2)+5)#

= #216-3*(18)+5#

= #216-54+5#

= #216+5-54#

= #221-54#

= #167#

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Answer 2

Eli Assouline

(6^3 - 3 \times (3^2 \times 2) + 5 = 216 - 3 \times (9 \times 2) + 5 = 216 - 54 + 5 = 167.)

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.