How do you simplify #(5x-15)/(x-3)#?

Answer 1

The value of this expression is #5#. See explanation.

First we have to find the domain of this rational expression:

#x-3 !=0 => x !=3#
The domain is #x in RR-{3}#

The value of this expression is:

#(5x-15)/(x-3)=(5(x-3))/(x-3)=5#
Answer: The value of this expressionm is 5 for all real numbers #x# different from 3
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Answer 2

To simplify (5x-15)/(x-3), you can factor out a common factor of 5 from the numerator, which gives you 5(x-3)/(x-3). Then, you can cancel out the common factor of (x-3) in the numerator and denominator, resulting in the simplified form of 5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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