How do you simplify # (5sqrt20 )/ sqrt5#?

Answer 1

Emery Allen

#(5sqrt20)/sqrt5=10#

#(5sqrt20)/sqrt5#

= #(5sqrt(2xx2xx5))/sqrt5#

= #(5xx2xxsqrt5)/sqrt5#

= #(5xx2xxcancelsqrt5)/(1cancel(sqrt5)#

= #5xx2=10#

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Answer 2

Zoe Adams

To simplify (\frac{5\sqrt{20}}{\sqrt{5}}), we can first simplify the square root in the denominator.

(\sqrt{5}) is already in its simplest form.

Next, we can simplify the numerator by breaking down (\sqrt{20}) into its prime factors:

(\sqrt{20} = \sqrt{4 \times 5} = \sqrt{4} \times \sqrt{5} = 2 \times \sqrt{5}).

Now, our expression becomes:

(\frac{5 \times 2 \times \sqrt{5}}{\sqrt{5}}).

Since the (\sqrt{5}) in the numerator cancels out with the (\sqrt{5}) in the denominator, we are left with:

(5 \times 2 = 10).

So, (\frac{5\sqrt{20}}{\sqrt{5}}) simplifies to (10).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.