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How do you simplify #-5i(10+2i)#?

Answer 1

Caleb Alexander

#10-50i#

distribute the bracket.

#rArr-5i(10+2i)=-50i-10i^2#

#color(orange)"Reminder : " i^2=(sqrt(-1))^2=-1#

#rArr-50i-10i^2=-50i+10=10-50i#

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Answer 2

Ariana Alvarez

To simplify the expression ( -5i(10 + 2i) ), follow these steps:

Distribute ( -5i ) across the terms inside the parentheses.
Combine like terms.
Perform any necessary simplifications.

Now, let's simplify the given expression:

[ -5i(10 + 2i) ]

Step 1: Distribute ( -5i ) across the terms inside the parentheses:

[ (-5i \times 10) + (-5i \times 2i) ]

Step 2: Multiply:

[ -50i - 10i^2 ]

Step 3: Simplify by recognizing that ( i^2 = -1 ):

[ -50i - 10(-1) ]

[ -50i + 10 ]

Therefore, the simplified expression is ( -50i + 10 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.