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How do you simplify #((5g^3)/h^2)/((6g)/(5h))#?

Answer 1

Abigail Allen

#=(25g^2)/(6h)#

#((5g^3)/h^2)/((6g)/(5h))#

#=(5g^3)/h^2times(5h)/(6g)#

#=(25g^2)/(6h)#

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Answer 2

Eva Abramson

To simplify ((5g^3)/h^2)/((6g)/(5h)), you can multiply the numerator and denominator of the first fraction by the reciprocal of the second fraction. This gives you (5g^3/h^2) * (5h/6g). Simplifying further, you can cancel out common factors: (5g^3 * 5h) / (h^2 * 6g). This simplifies to (25gh) / (6h^2).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.