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How do you simplify #(5c+5d )/ (c²+cd)#?

Answer 1

Abigail Allen

#(5c+5d )/ (c²+cd) = color(green)(5/c#

#(5c+5d )/ (c²+cd)#

5 is common to both the terms in the numerator, and c is common to both the terms in the denominator.

# = (5cancel((c + d))) / (c*cancel((c+d)))#

# = 5/c#

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Answer 2

Eli Assouline

To simplify (5c+5d)/(c²+cd), you can factor out a common factor of 5 from the numerator, resulting in 5(c+d). Then, you can factor out a common factor of c from the denominator, giving you c(c+d). Therefore, the simplified form is 5(c+d)/c(c+d).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.