# How do you simplify #( 5a^2 + 20a) /( a^3-2a^2) * ( a^2-a-12) / (a^2-16)#?

simplyfing the first equation:

having a common factor "a" a(5a+20)

Moving to the second equation:

By signing up, you agree to our Terms of Service and Privacy Policy

By factoring each expression in the numerator(top) and the denominator(bottom) and then cancelling out the commons.

Here's how we do it:

#(5acolor(red)cancel(color(black)((a+4))))/(a^2(a-2))*(color(green)cancel(color(black)((a-4)))(a+3))/(color(green)cancel(color(black)((a-4))) color(red)cancel(color(black)((a+4))))=(5a(a+3))/(a^2(a-2))=color(blue)((5(a+3))/(a(a-2)))#

By signing up, you agree to our Terms of Service and Privacy Policy

To simplify the expression (5a^2 + 20a) / (a^3-2a^2) * (a^2-a-12) / (a^2-16), we can factor the numerator and denominator of each fraction and cancel out any common factors.

First, let's factor the numerator and denominator of the first fraction: 5a^2 + 20a = 5a(a + 4) a^3 - 2a^2 = a^2(a - 2)

Next, let's factor the numerator and denominator of the second fraction: a^2 - a - 12 = (a - 4)(a + 3) a^2 - 16 = (a - 4)(a + 4)

Now, we can cancel out the common factors: (5a(a + 4))/(a^2(a - 2)) * ((a - 4)(a + 3))/((a - 4)(a + 4))

After canceling out the common factors, we are left with: (5(a + 4))/(a(a - 2)) * (a + 3)/(a + 4)

Therefore, the simplified expression is: (5(a + 4)(a + 3))/(a(a - 2)(a + 4))

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7