How do you simplify #5/(x+3) - 2/(x-1)#?

Answer 1

#(3x-11)/((x+3)(x-1))#
Where #x!=-3 or 1#

#(3x-11)/((x+3)(x-1))#
Where #x!=-3 or 1#
The reason x can't be -3 or 1 is because if this happens the denominator will become #0# and anything with denominator #0# becomes undefined.

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Answer 2
The given question states : #5/(x+3)-2/(x-1)#
So, processing further: #rArr(5 xx( x-1)-2 xx( x+3))/((x+3) xx (x-1)#
#rArr((5x-5 )-(2x+6))/((x+3) ( x-1)#
#rArr(5x-5-2x-6)/((x+3)(x-1)#
#rArr(5x-2x -5-6)/((x+3)(x-1)#
#rArr(3x-11) /((x+3) (x-1))#
#rArr(3x-11) /(x^2-x+3x-3)#
#rArr(3x-11) /(x^2+2x-3)#

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Answer 3

To simplify the expression 5/(x+3) - 2/(x-1), you need to find a common denominator for the two fractions. The common denominator is (x+3)(x-1).

Next, multiply the numerator and denominator of the first fraction, 5/(x+3), by (x-1), and multiply the numerator and denominator of the second fraction, 2/(x-1), by (x+3).

This gives you (5(x-1))/((x+3)(x-1)) - (2(x+3))/((x+3)(x-1)).

Now, simplify the numerators: 5(x-1) = 5x - 5, and 2(x+3) = 2x + 6.

Combine the fractions by subtracting the second fraction from the first: (5x - 5 - 2x - 6)/((x+3)(x-1)).

Simplify the numerator: (5x - 2x - 5 - 6) = 3x - 11.

The simplified expression is (3x - 11)/((x+3)(x-1)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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