How do you simplify #5(2^3+4)/sqrt 36 times 7# using PEMDAS?

Question

Eva Abramson · Accepted Answer

#70#

First, there are no explicitly written parentheses, but the numerator of the fraction must be computed first for the problem to make sense. This term is calculated by first computing #2^3# then adding four. The problem is then reduced to:

#5 xx 12/sqrt(36) xx7#

Next compute any terms with exponents. There is one exponent left which is hidden in the denominator. Note that #sqrt(36)=36^(1/2)#. Hence the problem is now

#5 xx 12/6 xx7#

Finally, perform all of the multiplication and division by moving left to right.

#5 xx 12/6 xx 7=60/6 xx 7=10 xx 7=70#

Julia Adams · Answer

undefined To simplify the expression using PEMDAS, follow this order:

1. Parentheses: Simplify within parentheses first.
2. Exponents: Perform any exponentiation.
3. Multiplication and Division: Perform multiplication and division from left to right.
4. Addition and Subtraction: Perform addition and subtraction from left to right.

Applying these steps:

1. Inside the parentheses: $2^3 + 4 = 8 + 4 = 12$.
2. Replace $2^3+4$ with $12$.
3. Simplify $5 \times 12 = 60$.
4. Simplify $\sqrt{36} = 6$.
5. Replace $\sqrt{36}$ with $6$.
6. Multiply $60 \times 6 = 360$.
7. Finally, multiply $360 \times 7 = 2520$.

So, the simplified expression is $2520$.