How do you simplify #5 2/3- 1 4/5#?

Answer 1

#58/15# or #3 13/15#

First convert these to fractions:

#((3*5)/3+ 2/3) - ((5*1)/5 + 4/5) =>#
#(15 + 2)/3 - (5 + 4)/5 =>#
#17/3 - 9/5#

Next get each fraction over a common denominator:

#(5/5)(17/3) - (3/3)(9/5) =>#
#85/15 - 27/15 =>#
#58/15# or #3 13/15#
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Answer 2

To simplify (5 \frac{2}{3} - 1 \frac{4}{5}), first convert both mixed numbers to improper fractions: (5 \frac{2}{3} = \frac{(5*3) + 2}{3} = \frac{15 + 2}{3} = \frac{17}{3})

(1 \frac{4}{5} = \frac{(1*5) + 4}{5} = \frac{5 + 4}{5} = \frac{9}{5})

Now, subtract the second fraction from the first one: (\frac{17}{3} - \frac{9}{5})

To subtract fractions with different denominators, find a common denominator: The least common denominator (LCD) of 3 and 5 is 15.

Rewrite the fractions with the LCD: (\frac{17}{3} = \frac{175}{35} = \frac{85}{15})

(\frac{9}{5} = \frac{93}{53} = \frac{27}{15})

Now, subtract the fractions: (\frac{85}{15} - \frac{27}{15} = \frac{85 - 27}{15} = \frac{58}{15})

So, (5 \frac{2}{3} - 1 \frac{4}{5} = 3 \frac{13}{15}).

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Answer 3

To simplify (5\frac{2}{3} - 1\frac{4}{5}), follow these steps:

  1. Convert the mixed numbers to improper fractions: (5\frac{2}{3}) as an improper fraction is ( \frac{(5 \times 3) + 2}{3} = \frac{15 + 2}{3} = \frac{17}{3} ) (1\frac{4}{5}) as an improper fraction is ( \frac{(1 \times 5) + 4}{5} = \frac{5 + 4}{5} = \frac{9}{5} )

  2. Subtract the fractions: (\frac{17}{3} - \frac{9}{5})

  3. To subtract fractions, they must have the same denominator. So, find a common denominator, which is the least common multiple (LCM) of 3 and 5, which is 15.

  4. Rewrite the fractions with a common denominator: ( \frac{17}{3} = \frac{17 \times 5}{3 \times 5} = \frac{85}{15} ) ( \frac{9}{5} = \frac{9 \times 3}{5 \times 3} = \frac{27}{15} )

  5. Now, subtract the fractions: ( \frac{85}{15} - \frac{27}{15} = \frac{85 - 27}{15} = \frac{58}{15} )

  6. Convert the improper fraction back to a mixed number: ( \frac{58}{15} = 3\frac{13}{15} )

Therefore, (5\frac{2}{3} - 1\frac{4}{5} = 3\frac{13}{15}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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