How do you simplify #(4x-9)/(2x-3)#?

Answer 1

#(4x-9)/(2x-3)=color(blue)(2-3/(2x-3))color(white)"xxxxx"#...but it is not clear that this is a "simplification"

Since this was asked under "Excluded Values for Rational Expression" perhaps it should be noted that #color(white)("XXX")(4x-9)/(2x-3)# is not defined if #(2x-3)=0 rarr x=3/2#
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Answer 2

#2-3/(2x-3)#

Given: #(4x-9)/(2x-3)#

beginning the short version of the long division process

#color(white)("ddddd.ddddd")4x-9# #color(magenta)(2)(2x-3)-> ul(4x-6larr" Subtract")# #color(white)("dddddddddddd")0color(magenta)(-3 larr" Remainder")#
#(4x-9)-:(2x-3) = color(magenta)(2-3/(2x-3))#
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Answer 3

To simplify the expression (4x-9)/(2x-3), you can use the method of polynomial long division or synthetic division. Alternatively, you can also factorize the numerator and denominator and cancel out any common factors.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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