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How do you simplify #4x^2+3x+1-8x#?

Answer 1

Abigail Allen

#4x^2+3x+1-8x#

#=4x^2+3x-8x+1#

#=4x^2+(3-8)x+1#

#=4x^2-5x+1#

#=(4x-1)(x-1)#

By the way, there are a few ways to identify this final step, including this little tip:

Given #4x^2-5x+1#, extract the digits to get #451# and factor that to get #41xx11#. Then taking the #-# sign into account, #41# becomes #(4x-1)# and #11# becomes #(x-1)#. (This only works if the multiplication involves no carrying of digits)

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Answer 2

Genesis Allen

To simplify 4x^2 + 3x + 1 - 8x, you combine like terms:

4x^2 - 8x + 3x + 1

Combine -8x and 3x:

4x^2 - 5x + 1

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.