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How do you simplify #4sqrt8*sqrt2#?

Answer 1

Abigail Allen

1) #4sqrt(4xx2)*sqrt2#

2) #(4sqrt4*sqrt2#) ⋅ #sqrt2#

3) #4xx2sqrt2*sqrt2#

4) #8*2#

5) #16#

1) Find factors of #8# under the radical. 2) Simplify #sqrt4# to #2# and multiply by the #4# outside 3) Multiply #8sqrt2*sqrt2" "(larrsqrt2*sqrt2# equals 2) 4) #8*2# 5) #16#

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Answer 2

Avery Alexander

#=16#

The two square roots can be combined into one. In this case this is a good idea because the product will be a prefect square.

#4sqrt8 xx sqrt2 = 4sqrt(8xx2) #

#= 4 sqrt(16)#

#= 4xx4#

#=16#

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Answer 3

Genesis Allen

To simplify 4√8 * √2, we can combine the square roots and simplify the expression. The square root of 8 can be simplified as 2√2. Therefore, the expression simplifies to 4 * 2√2 * √2, which further simplifies to 8√2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.